Question 1
Which of the following best describes the closure property of integers under multiplication?No clue? Show me the answer
Correct answer
Correct!
IncorrectStep-by-step walkthrough
Choose a solution method
Method #1Direct ApproachStep 1: Recall the definition of closure
A set is closed under an operation if performing that operation on any two members always produces a result that is also in the set. Here we are asking about integers under multiplication.
Step 2: Test with examples
For example, , which is an integer. Also, , also an integer. No matter which two integers we multiply, the result is always an integer.
Step 3: Choose the correct answer
The closure property under multiplication means: multiplying two integers always gives an integer. This matches the first option exactly.
Method #2Process of EliminationStep 1: Identify what is being asked
We need the statement that correctly describes closure of integers under multiplication — meaning the result stays in the set of integers.
Step 2: Eliminate 'always gives a positive number'
'Multiplying two integers always gives a positive number' is false. For example, , which is negative. Eliminate this option.
Step 3: Eliminate 'order does not matter'
'The order in which you multiply integers does not matter' describes the commutative property, not closure. Eliminate this option.
Step 4: Eliminate 'multiplying by 1 leaves it unchanged'
'Multiplying an integer by 1 leaves it unchanged' describes the multiplicative identity, not closure. Eliminate this option.
Step 5: Select the correct answer
The remaining option — 'Multiplying two integers always gives an integer' — correctly describes closure: the result stays within the set of integers.
Question 2
A student claims that the set of integers is closed under division because . Which response best evaluates this claim?No clue? Show me the answer
Correct answer
Correct!
IncorrectStep-by-step walkthrough
Choose a solution method
Method #1Direct ApproachStep 1: Understand what closure requires
For closure to hold, the operation must always produce a result in the set — not just sometimes. One counterexample is enough to disprove closure.
Step 2: Find a counterexample
Consider . Both 3 and 4 are integers, but is not an integer. This single counterexample proves integers are not closed under division.
Step 3: Evaluate the student's reasoning
The student used one case where division happened to give an integer (), but closure requires it to work for all pairs of integers, not just some. The student's reasoning is flawed.
Step 4: Choose the correct answer
The correct response points out that is a counterexample, showing the claim is incorrect.
Method #2Process of EliminationStep 1: Identify the key question
We need to decide whether the student's claim (integers are closed under division) is valid, and find the best evaluation.
Step 2: Eliminate both 'correct' options
'The claim is correct because dividing two integers sometimes gives an integer' and 'The claim is correct because 3 is an integer' both agree with the claim. But closure requires the result to always be an integer, not just sometimes. Eliminate both.
Step 3: Eliminate 'incorrect because division is not commutative'
'The claim is incorrect because division is not commutative' confuses two different properties — commutativity and closure. Lack of commutativity is irrelevant to closure. Eliminate this option.
Step 4: Select the correct answer
'The claim is incorrect because , which is not an integer' is the only response that correctly uses a counterexample to disprove the closure claim.
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