Question 1
A child is born with cystic fibrosis. Neither parent has the disease. Which genotypes must both parents have?No clue? Show me the answer
Correct answer
Correct!
IncorrectStep-by-step walkthrough
Choose a solution method
Method #1Direct ApproachStep 1: Identify the type of disorder
Cystic fibrosis is a recessive genetic disorder. The faulty allele is f, and the normal allele is F.
Step 2: Determine the affected child's genotype
For a child to have cystic fibrosis, they must have two copies of the faulty allele. Therefore the child's genotype is ff.
Step 3: Work backwards to the parents
Since the child is ff, they must have received one f allele from each parent. Because the parents are unaffected, they each have one normal allele masking the faulty one.
Step 4: Determine the parent genotype
Each parent must be Ff — carrying one normal allele (F) and one faulty allele (f). These individuals are called carriers: phenotypically healthy but able to pass the recessive allele to their children.
Method #2Process of EliminationStep 1: Identify what is being asked
We need to find the parent genotypes when two unaffected parents have a child with cystic fibrosis (a recessive disorder).
Step 2: Eliminate FF
If both parents were FF, they could only pass F alleles to their children. No child could ever be ff, so this option is impossible.
Step 3: Eliminate ff
If both parents were ff, they would have cystic fibrosis themselves — but the question states neither parent has the disease. This option is eliminated.
Step 4: Eliminate Ff or FF
If one parent were FF, they could only contribute an F allele. An ff child would be impossible unless both parents contribute f alleles. Since both parents must be carriers, 'Ff or FF' is not the precise answer.
Step 5: Select the correct answer
Both parents must be Ff (carriers) — this is the only genotype that is unaffected yet can produce an ff child when two carriers have children together.
Question 2
Which of the following best explains why dominant genetic disorders rarely skip generations?No clue? Show me the answer
Correct answer
Correct!
IncorrectStep-by-step walkthrough
Choose a solution method
Method #1Direct ApproachStep 1: Recall the key property of dominant alleles
A dominant allele is expressed in the phenotype even when only one copy is present. This means any individual who inherits the allele — whether homozygous dominant or heterozygous — will show the disorder.
Step 2: Connect this to generation skipping
Because there are no silent carriers for dominant disorders, the faulty allele cannot be hidden in an unaffected individual and passed on without being noticed. Every individual who inherits the allele is affected.
Step 3: Select the correct explanation
The disorder appears in every generation because anyone with the dominant allele shows the disorder — there is no way for the allele to 'skip' through an unaffected individual.
Method #2Process of EliminationStep 1: Identify what the question asks
The question asks why dominant disorders don't skip generations — we need the correct mechanistic explanation.
Step 2: Eliminate 'dominant alleles are more common'
Dominant does not mean more common. The notes explicitly warn against this misconception. Frequency in the population is a separate concept from dominance.
Step 3: Eliminate 'late onset in old age'
While Huntington's disease has late onset, this is a feature of one specific dominant disorder. It is not the reason why dominant disorders in general don't skip generations — in fact, late onset means some affected individuals have children before knowing they're affected.
Step 4: Eliminate 'only affects males'
Autosomal dominant disorders like Huntington's disease affect both males and females equally. This option describes X-linked inheritance, not autosomal dominant.
Step 5: Select the correct answer
The correct answer is that anyone who carries the dominant allele shows the disorder — because one copy is sufficient for expression, there are no hidden carriers to cause a skipped generation.
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