Liquid Pressure

We are given the force $F=10$ N and the area $A=0.0001$ m². We need to find the pressure $P$.

The formula for pressure is: $P=\frac{F}{A}$ Substituting the values: $P=\frac{10}{0.0001}$

$P=\frac{10}{0.0001}=100,000\text{ Pa}$ This is a very large pressure, which explains why a small tack can easily pierce a surface despite a modest applied force.

The pressure exerted by the tip is 100,000 Pa.

We need to calculate the pressure using $P=F/A$ with $F=10$ N and $A=0.0001$ m².

0.001 Pa would result from multiplying $F\times A=10\times 0.0001$, which is incorrect. The formula divides force by area, not multiplies.

1,000 Pa and 10,000 Pa are incorrect because $10÷0.0001=10\times 10,000=100,000$, not 1,000 or 10,000. These likely come from arithmetic errors with the decimal.

The correct calculation gives $P=10÷0.0001=$ 100,000 Pa.

We have $\rho =1000$ kg/m³, $g=10$ N/kg, and $h=8$ m. The question asks for liquid pressure only.

$P=\rho gh=1000\times 10\times 8$

$P=1000\times 10\times 8=80,000\text{ Pa}$

The liquid pressure at 8 m depth is 80,000 Pa.

We use $P=\rho gh$ with $\rho =1000$ kg/m³, $g=10$ N/kg, $h=8$ m.

800 Pa would result from $1000\times 8÷10$ or some other incorrect arrangement of the formula. This ignores the correct multiplication of all three values.

8,000 Pa could come from using only $g\times h=10\times 8=80$, then wrongly treating it as 8,000. It omits the density factor of 1000.

800,000 Pa might come from a decimal error, such as using $\rho =10,000$ instead of 1000. This is ten times too large.

$1000\times 10\times 8=$ 80,000 Pa is the correct result.