Work Done and Power

We are given the force $F=40\text{ N}$ and the distance $d=7\text{ m}$. The force and motion are in the same direction, so the full formula applies.

Use the formula $W=F\times d$ Substituting the values: $W=40\text{ N}\times 7\text{ m}=280\text{ J}$

The work done on the crate is 280 J. Remember that joules (J) are the unit of work done and energy transferred.

We need to find the work done using $W=F\times d$, where $F=40\text{ N}$ and $d=7\text{ m}$.

47 J would come from adding $40+7=47$, but work is calculated by multiplying force and distance, not adding them.

5.7 J would come from dividing $40÷7\approx 5.7$, which gives force per distance — not work done.

140 J might come from halving the correct answer, perhaps confusing the formula. There is no reason to divide by 2 here.

$W=40\times 7=280\text{ J}$, so 280 J is correct.

For work to be done, the object must move in the direction of the applied force. Here, the barbell is held still — there is no displacement ($d=0\text{ m}$).

$W=F\times d=600\text{ N}\times 0\text{ m}=0\text{ J}$ Even though a large force is applied, no work is done because there is no movement.

The work done is 0 J. The weightlifter may feel tired due to muscular effort, but in physics, no work is done on the barbell without displacement.

We need to determine how much work is done when a force is applied but the object does not move.

6000 J would come from $600\times 10$, but time is not part of the work formula. This confuses work with a power calculation.

60 J might come from $600÷10$, which has no physical meaning in this context. Division of force by time is not a standard formula here.

600 J treats the force value alone as the answer, ignoring that $W=F\times d$ and $d=0$ because the barbell does not move.

Since displacement $d=0$, $W=600\times 0=\text{0 J}$. No movement means no work done in physics.